The hypotenuse of a right angled triangle is 6 metres more than twice the shortest side

Let the shortest side of the triangle be x m. Then, Hypotenuse = (2x + 6) m and third side = (2x + 6 – 2) m = (2x + 4) m According to Pythagoras theorem, we have (2x + 6)2 = x2 + (2x + 4)2 ? 4x2 + 24x + 36 = x2 + 4x2 + 16x + 16 ? 24x - 16x + 36 - 16 = x2